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> Modulus Operator, Simple Shell Script
post Jun 12 2008, 06:55 AM
Post #1

Whats this Lie-nix Thing?

Group: Members
Posts: 1
Joined: 12-June 08
Member No.: 13,504

Alright, I am attempting to add records to a database, but I need them to be divisible by 30 so that I can update them concurrently.
In order to do this I intended to use `date +%s` to get the current time in seconds, and then add 1 until the number was divisible by 30.
To simplify things I made $now equal to a number I knew was divisible by 30 for testing, but the modulus operator doesn't work.
I'm assuming my syntax is wrong, but everything I've looked at makes it look right to me. The increment operator wouldn't work either...
Any help would be much appreciated because I'm at a standstill with this nonsense. Thanks.

#now=`date +%s`

if [ $now%30 != 0 ]
while [ $now%30 != 0 ]
tmp=`expr $now + 1`

echo $now
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Posts in this topic
- etangman   Modulus Operator   Jun 12 2008, 06:55 AM
- - michaelk   Lots of help can be found on bash shell scripts by...   Jun 13 2008, 05:58 PM

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