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> Scripting help, Removing everything from a log file before a character
jennyjebson
post Dec 3 2007, 06:49 AM
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Hello,

I am a newbie, and need a little assistance!

I have an application that is running on Linux that produces a log file.

The information in the log file is produced by purely enabling the debug option in the application, however there is far too much

non useful information in the log files produced.

I would like to cut out some of the information in the log file... there seems to be a unique character after which I think is useful information.

So I would like to remove all characters before this unique character on each line "|" and output this to a new log file.

Firstly, is this possible? as anyone able to help me make a little script?

Here is an excerpt from the the log file produced:

30-11 11:55:06 expect: Timeout(30) Max Len(60) EndLen(2) FailFlag(0) StartLen(0)
30-11 11:55:06 toggle_HUP: Hangup line
30-11 11:55:08 sending command:
0D 0A | ..

30-11 11:55:11 expect: Timeout Occured

30-11 11:55:11 main: Failed - Next Command = 10
30-11 11:55:11 expect: Timeout(10) Max Len(50) EndLen(0) FailFlag(0) StartLen(0)
30-11 11:55:14 sending command:
0D 0A 0D 0A | ....

30-11 11:55:15 expect: Timeout Occured

30-11 11:55:15 main: Success - Next Command = 50
30-11 11:55:15 expect: Timeout(40) Max Len(1600) EndLen(5) FailFlag(0) StartLen(4)
30-11 11:55:16 sending command:
0D 40 30 31 20 68 20 31 0D | .@01 h 1.

30-11 11:55:16 expect: Found Start String
30-11 11:55:16 expect Found Reply String (position 357) (minLen 0)
30 31 0D 0A 23 0D 0A 0D 0A 32 30 30 37 2D 31 31 | 01..#....2007-11
2D 32 38 20 20 32 33 3A 35 30 2C 30 31 2C 48 31 | -28 23:50,01,H1
34 2C 52 4F 53 41 0D 0D 0A 30 31 20 20 20 39 2E | 4,ROSA...01 9.
39 3B 30 32 20 20 20 20 37 37 3B 30 33 20 20 20 | 9;02 77;03

Is anyone able to help me?

Thanks,

jenny
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michaelk
post Dec 3 2007, 04:06 PM
Post #2


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So what is this application? What are you trying to accomplish? IMHO the entire log file has useful information.

What is you see is the hex number that corresponds to the ASCII character displayed on the right side of the |. The | is not real data and it is referred to as a pipe
pipe character in linux speak. This format is typical of hex file viewers/editors. If there isn't a readable character for the hex code i.e. [A-Z, a-z, 0-9] etc then a "."
is used. A 0D 0A is a carriage return, line feed sequence.

30 31 0D 0A 23 0D 0A 0D 0A 32 30 30 37 2D 31 31 | 01..#....2007-11
2D 32 38 20 20 32 33 3A 35 30 2C 30 31 2C 48 31 | -28 23:50,01,H1
34 2C 52 4F 53 41 0D 0D 0A 30 31 20 20 20 39 2E | 4,ROSA...01 9.
39 3B 30 32 20 20 20 20 37 37 3B 30 33 20 20 20 | 9;02 77;03

What you would see if viewing from a text editor, vi, kedit, notepad etc is:
01
#

2007-11-28 23:50,01,H14,ROSA
01___9.9;02 77;03___

I've used a "_" to display spaces i.e the hex character 20. If you want to know more about ACSII text characters you can find lots of info by googling.
From what I have gathered from the log file this is a response string from the transmitted command. What you want is possible but might remove
raw information that could be important.
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